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10x^2-56=88-6x
We move all terms to the left:
10x^2-56-(88-6x)=0
We add all the numbers together, and all the variables
10x^2-(-6x+88)-56=0
We get rid of parentheses
10x^2+6x-88-56=0
We add all the numbers together, and all the variables
10x^2+6x-144=0
a = 10; b = 6; c = -144;
Δ = b2-4ac
Δ = 62-4·10·(-144)
Δ = 5796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5796}=\sqrt{36*161}=\sqrt{36}*\sqrt{161}=6\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{161}}{2*10}=\frac{-6-6\sqrt{161}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{161}}{2*10}=\frac{-6+6\sqrt{161}}{20} $
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